Force acting on the bullet is given as
⇒ F=600−2×105t
⇒ t=600/2×105
t = 3×10−3s
Now impulse imparted by the bullet is I=
So, we get ⇒I=|600t−2×105t2/2|3×10−3
∴ I = 0.9Ns
A bullet is fired from a gun, the force on the bullet is given by F=600−2×105t where F is in newton and t in second. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to a bullet?
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