A block of mass 2 kg is placed on the floor (μ = 0.4). a horizontal force of 7 n is applied on the block. the force of friction between the block and floor is

Published On: July 15, 2022

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The mass of the block as given in the question is 2kg.

The coefficient of static friction is 0.4.

Force applied on the block is Fnet = 2.8N

The force of friction between the block and the floor =?

Limitng friction =μN = 0.4 × 2 × 10 = 8N

As applied force is less than limiting friction

so Force of friction on block=Applied external force=7N