Answer: 21%
The relationship between the kinetic energy and momentum of a body is K.E=P2/2m.
Given that, if momentum is increased by 10%, then by what % the K.E will increase. So, the initial momentum be P and initial kinetic energy be K.E=P2/2m.
Increase in momentum = 10% of P, i.e.
ā10/100ĆP =P/10 So, final momentum = initial momentum + increased momentum.
Final momentum, P1 = P + P/10 =11P/10. Then, final kinetic energy,
āK.E1 = (P1)2/2m
We have final momentum = 11P/10, putting this value,
we get āK.E1=(11P/10)2/2m = 121P2/2mĆ100
āK.E1=121/100 Ć P2/2m = 121/100 K.E.
Now, increase in kinetic energy = final kinetic energy ā initial kinetic energy. increase in kinetic energy =121/100K.E ā K.E
increase in kinetic energy =121K.Eā100K.E/100
increase in kinetic energy =21K.E/100
% increase in kinetic energy. ā21%
Hence, we can see that if the momentum of an object increases by 10%, then the kinetic energy will increase by 21%.







