Google News

Two resistors whose value are in ratio 2:1 are connected in parallel with one cell. Then ratio of power dissipated is

By Admin

Published On:

Follow Us

Join Telegram Channel

Join Now

Join Telegram Group

Join Now

 The heat developed is given by H = V2t/R

⇒ HHalf/Hfull = (RFull/RHalf) = R/R/2 = 2

Therefore,

HHalf = 2 × HFull

Join Telegram Channel

Join Now

Join Telegram Group

Join Now

Leave a Comment